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Q.

In a ΔABC,a(cos2C+cos2B)+cosA(ccosC+bcosB)=

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a

b

b

c

c

a

d

a+b+c

answer is A.

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Detailed Solution

a(cos2C+cos2B)+cosA(ccosC+bcosB)=acos2C+acos2B+ccosCcosA+bcosAcosB=cosC(acosC+ccosA)+cosB(acosB+bcosA)bcosC+ccosB=a

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