In ΔABC, AC = BC and ∠C = 110°. Find ∠A and ∠B.

Given in ΔABC, ∠C = 110°
Let, ∠A = ∠B = x° (Angle opposite to equal sides of a triangle are equal)
x + x + 110° = 180°
$\Rightarrow$ 2x + 110° = 180°
$\Rightarrow$ 2x = 180° – 110°
$\Rightarrow$ 2x = 70°
$\Rightarrow$ x = 35°
$\Rightarrow$ ∠A = ∠B = 35°