In ΔABC, if ∠A +  ∠B = 125° and ∠A +  ∠C = 113°, then what is the value of ∠A ?

Given, In ΔABC, if ∠A +  ∠B = 125° and ∠A +  ∠C = 113°.
The addition of all angles in a triangle is 180°.
∠A +  ∠B + ∠C = 180°
125° + ∠C = 180°
∠C = 180° - 125°
∠C = 55°
∠A +  ∠C = 113°
∠A + 55° = 113°
∠A = 113° - 55°
∠A = 58°
So, the value of ∠A is 58°.
Hence, option 3 is correct.