In $\mathrm{△}\mathrm{ABC}$ The coordinates of the vertex $\mathrm{A} (-3,1)\mathrm{. }$If the equation of the median through B is $2\mathrm{x}+\mathrm{y}-3=0$ and the equation of the bisector of angle  C is $7\mathrm{x}-4\mathrm{y}-1=0$ then the equation of the side BC is

Vertex $\mathrm{A} (-3,1)$

Median through the vertex B is $2\mathrm{x}+\mathrm{y}-3=0$

Vertex C is (h,k)

Median through B meets midpoint of  AC

Midpoint$=\left(\alpha ,\frac{3-2\alpha }{3}\right)$ and midpoint of AC is $=\left(\frac{h-3}{2},\frac{k+1}{2}\right)$

$\left(\alpha ,\frac{3-2\alpha }{3}\right)$$=\left(\frac{h-3}{2},\frac{k+1}{2}\right)$

$h=2\alpha +3$ and $k=\frac{3-4\alpha }{3}$

(h,k) lies on angle bisector $7\mathrm{x}-4\mathrm{y}-1=0$ then 

$7\left(2\alpha +3\right)-4\left(\frac{3-4\alpha }{3}\right)-1=0$

$\alpha =\frac{-12}{17}$

point $C=\left(\frac{27}{17},\frac{33}{17}\right)$ and Image of vertex A with respect to angle bisector is lies on line BC

then find BC equation

Side BC is $18\mathrm{x}-\mathrm{y}=49$