In ∆ABCs-a∆=18, s-b∆=112,s-c∆=124then b =

s-a∆=18, s-b∆=112, s-c∆=124 r1=8, r2=12, r3=24 b=r3+r1 r r2r3 r1 1r=18+112+124 1r=624=14 b=(24+8) 4(12)8(24) b=322=16

In ∆ABCs-a∆=18, s-b∆=112,s-c∆=124then b =

s-a∆=18, s-b∆=112, s-c∆=124 r1=8, r2=12, r3=24 b=r3+r1 r r2r3 r1 1r=18+112+124 1r=624=14 b=(24+8) 4(12)8(24) b=322=16

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In $∆ ABC \frac{(s - a)}{∆} = \frac{1}{8}, \frac{(s - b)}{∆} = \frac{1}{12}, \frac{(s - c)}{∆} = \frac{1}{24}$ then b =

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Detailed Solution

$\frac{s - a}{∆} = \frac{1}{8}, \frac{s - b}{∆} = \frac{1}{12}, \frac{s - c}{∆} = \frac{1}{24} r_{1} = 8, r_{2} = 12, r_{3} = 24 b = (r_{3} + r_{1}) \sqrt{\frac{r r_{2}}{r_{3} r_{1}}} \frac{1}{r} = \frac{1}{8} + \frac{1}{12} + \frac{1}{24} \frac{1}{r} = \frac{6}{24} = \frac{1}{4} b = (24 + 8) \sqrt{\frac{4 (12)}{8 (24)}} b = \frac{32}{2} = 16$