In above problem ratio of distance traveled in first second of upward motion to first second of downward motion is

The distance covered in first second of upward motion

h₁​ = ut − 1/2​gt²

h₁​ = 50(1) − 1/2​×10×(1)²

h₁ ​= 50 − 5 = 45 m

The distance covered by the body in first second of downward motion

h₂​ = ut − 1/2​gt²

u = 0

h₂​ = 1/2×10×(1)²

h₂​ = 5

ratio can be obtained as:

h₁/​h₂​​ = 45/5​ = 9:1