In acidic medium, equivalent weight of K2Cr2O7 (mol. wt.= M) is

Cr2O72− + 14H+ + 6e- → 2Cr3+ + 7H2OEquivalent weight of K2Cr2O7=Molecular Mass6 = 294.26 =M6

In acidic medium, equivalent weight of K2Cr2O7 (mol. wt.= M) is

Cr2O72− + 14H+ + 6e- → 2Cr3+ + 7H2OEquivalent weight of K2Cr2O7=Molecular Mass6 = 294.26 =M6

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In acidic medium, equivalent weight of K₂Cr₂O₇ (mol. wt.= M) is

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M/3

M/4

M/6

M/2

answer is C.

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${Cr}_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} \to 2 {Cr}^{3 +} + 7 H_{2} O$
Equivalent weight of $K_{2} {Cr}_{2} O_{7}$
$= \frac{Molecular Mass}{6} = \frac{294.2}{6} = \frac{M}{6}$

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In acidic medium, equivalent weight of K2Cr2O7 (mol. wt.= M) is

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In acidic medium, equivalent weight of K₂Cr₂O₇ (mol. wt.= M) is