In acidic medium, ${\mathrm{KMnO}}_4$ acts as a strong oxidizing agent. Its equivalent mass is molar mass divided by

Mn is in the +7 state in KMnO₄, which is a potent oxidizing agent. There is a change of 5 electrons in acidic medium.

${\mathrm{MnO}}_4^{-} +8{\mathrm{H}}^{+}+5{\mathrm{e}}^{-}\to {\mathrm{Mn}}^{2+}+4{\mathrm{H}}_2\mathrm{O}$