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In alkaline medium, $C l O_{2}$ oxidizes $H_{2} O_{2}$ to oxygen and is reduced to $C l^{-}$ . How many moles of $H_{2} O_{2}$ are oxidized by one mole of $C l O_{2}$ ?

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1.5

2.5

3.5

answer is B.

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Detailed Solution

$[2 C l O_{2} + 5 H_{2} O_{2} + 2 O H^{-} \to 2 C l^{-} + 5 O_{2} + 6 H_{2} O]$

2 moles of $C l O_{2} \equiv$ 5 moles $H_{2} O_{2}$

1 mole of $C l O_{2} \equiv$ 2.5 moles of $H_{2} O_{2}$ ]

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