In amplitude modulation the message signal $v_{m} = 10 \sin (2 π \times 10^{5} t)$ volts and carrier signal $V_{c} (t) = 20 \sin (2 π \times 10^{7} t)$ V. The modulated signal now contains message signal with lower side band and upper side band frequency. Therefore the band width of modulated signal is $α$ kHz, the value of “ $α$ ” is

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200

100

answer is A.

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Detailed Solution

Given

$\begin{array}{l} v_{m} = 10 \sin (2 π \times 10^{5} t) \\ v_{m} = 10 \sin (2 π f_{m} t) \\ f_{m} = 10^{5} H z \end{array}$

The bandwidth is

$\begin{array}{l} B . W = 2 f_{m} \\ = 2 \times 10^{5} H z \\ = 200 K H z \end{array}$
The value of $α = 200$

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