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Q.

In an AC circuit the voltage and current are described by $V = 200 \sin (314 t - \frac{π}{6})$ volts and $i = 50 \sin (314 t + \frac{π}{6}) m A$ respectively. The average power dissipated in the circuit is

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a

2.5 watt

b

5.0 watt

c

10.0 watt

d

50.0 watt

answer is A.

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Detailed Solution

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$P_{a v g} = I_{r m s} E_{r m s} \cos ϕ$ (Phase difference between current and voltage is $ϕ = \frac{π}{3}$

$= \frac{50 \times 200}{2} \times 10^{- 3} \cos \frac{π}{3} = 2.5 W$

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