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In an a.c. circuit the voltage applied is $E = E_{0} \sin ω t$ . The resulting current in the circuit is given by $I = I_{0} \sin (ω t - \frac{π}{2})$ . The power consumption in the circuit is given by

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$P = \sqrt{2} E_{0} I_{0}$

$P = \frac{E_{0} I_{0}}{\sqrt{2}}$

$P = z e r o$

$P = \frac{E_{0} I_{0}}{2}$

answer is C.

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Detailed Solution

In this case the voltage applied and current in the circuit are always at a phase difference of 90^o.

Since Cos(90)=0.

The power consumption in the given circuit will be zero.

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