In an ac circuit, V and I are given by V=100sin(100 t) volts, I=100sin (100t+π3) mA. The power dissipated in circuit is

P=Vr.m.s.×ir.m.s.×cosφ =1002×100×10−32×cosπ3 =104×10−32×12=104=2.5 watt

P=Vr.m.s.×ir.m.s.×cosφ =1002×100×10−32×cosπ3 =104×10−32×12=104=2.5 watt

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In an ac circuit, V and I are given by $V = 100 \sin (100 t)$ volts, $I = 100 \sin (100 t + \frac{π}{3}) mA$ . The power dissipated in circuit is

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$P = V_{r . m . s .} \times i_{r . m . s .} \times \cos φ$

$= \frac{100}{\sqrt{2}} \times \frac{100 \times 10^{- 3}}{\sqrt{2}} \times \cos \frac{π}{3}$

$= \frac{10^{4} \times 10^{- 3}}{2} \times \frac{1}{2} = \frac{10}{4} = 2.5 w a t t$

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