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In an ac generator, if coil of N turns and area A is rotated at $ν$ revolutions per second in a uniform magnetic field B, then the motional emf produced is equal to
(At t=0 s, the coil is perpendicular to the field)

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NBA $(2 π ν) \sin (2 π ν t)$

NBA² $(2 π ν) \sin (2 π ν t)$

$N^{2} B^{2} A^{2} (2 π ν) \sin (2 π ν t)$

$NBA (4 π ν) \sin (2 π ν t)$

answer is A.

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Detailed Solution

$Flux, ϕ = B (NA) \cos (ω t)$

$|e| = N B A ω \sin ω t$ ; $ω = 2 π ν$

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