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Q.

In an adiabatic process, the density of a diatomic gas becomes 32 times of its initial value. The final pressure of the gas is found to be n times the initial pressure. The value of n is

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a

32

b

326

c

128

d

132

answer is C.

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Detailed Solution

Given that density of the gas becomes 32 times and we know that density ρ is inversely proportional to volume V.

So, volume becomes 132 times of initial volume. In adiabatic process.

pVγ= constant p1V1γ=pfVfγ Now ,γ=75 for diatomic gas

pfpi=ViVf=(32)75=128

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