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In an adsorption experiment a graph between log x/m vs. log p is found to be linear with a slope of 45°. The intercept on the Y - axis was found to be 0.3010. What is x/m if pressure is 0.6 bar (tan 45° = 1)

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1.2

2.4

0.6

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answer is B.

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Detailed Solution

$\frac{x}{m} = {kp}^{1 / n} \log \frac{x}{m} = logk + \frac{1}{n} logp Slope = \frac{1}{n} = tanθ = \tan 45 ° = 1 i . e . n = 1 logk = 0.3010 or k = antilog (0.3010) = 2 At p = 0.6 atm, \frac{x}{m} = {kp}^{1 / n} = 2 \times {(0.6)}^{1} = 1.2$

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