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Q.

In an ammeter 0.2% of the main current passes through the galvanometer. If the resistance of the galvanometer is G, the resistance of the ammeter will be.


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a

G500 Ω

b

G600Ω

c

G700Ω

d

G300 Ω 

answer is A.

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Detailed Solution

Concept:  The potential difference between the two resistances is equal, according to the circuit schematic. Here, galvanometer resistance (G) equals current (I) through the galvanometer
Using a galvanometer, build an ammeter, voltmeter, and wattmeter.
As given in the question,
I(G) =0.2% of I
0.2100I  OR 1500I
Current passing through shunt
I(S) = I- I(G) 
= I- 1500 I
=499500I
Shunt and Galvanometer are in parallel series
S= G499
Resistance = 1G+1S
=1G+1G499
=500G
Resistance= G500
Question ImageHence, the correct option is 1.
 
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