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Q.

In an amplitude modulator circuit, the carrier wave is given by C(t)=4sin(20000πt) while modulating signal is given by, m(t)=2sin(2000πt). The value of modulation index and lower side band frequency are

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a

0.5  and  9kHz

b

0.4  and  10kHz

c

0.3  and  9kHz

d

0.5  and  10kHz

answer is D.

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Detailed Solution

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Given: carrier wave c(t)=4sin(20000πt)

Modulating signal, m(t)=2sin(2000πt)

So, carrier wave's amplitude and frequency are Ac=4V

ωc=20000π=2π×104 rad/s

fc=ωc2π=104Hz=10kHz

And modulating signals amplitude and frequency are 

Am=2V,wm=2000π=2π×103rad/s

fm=ωm2π=103Hz=1kHz

So, modulating Index: m=AmAc=24=12=0.5

lower side and upper side band frequency:

fLSB=fcfm =10-1=9 kHz

fUSB=fc+fm=10+1=11 kHz

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