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In an A.P., the sum of first n terms is $\frac{3 n^{2}}{2} + \frac{13 n}{2}$ . Then its 25^th term

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Detailed Solution

We have given that

S_{n} = \frac{3 n^{2}}{2} + \frac{13 n}{2}

25^th term $=$ Sum of 25^th terms $-$ Sum of 24 terms $= S_{25} - S_{24}$

Now, $S_{25} = 1100$ and $S_{24} = 1020$

$∴$ 25^th term $= 1100 - 1020 = 80$

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