In an apparatus the electric field was found to oscillate with an amplitude $36 V m^{- 1} .$ The rms value of the oscillating magnetic field is

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$8.5 \times 10^{- 8} T$

$6.5 \times 10^{- 8} T$

$9.5 \times 10^{- 8} T$

$7.1 \times 10^{- 8} T$

answer is A.

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Detailed Solution

$B_{0} = \frac{E_{0}}{C} = \frac{36}{3 \times 10^{8}} = 12 \times 10^{- 8} T B_{r m s} = \frac{B_{0}}{\sqrt{2}} = \frac{12 \times 10^{- 8}}{\sqrt{2}} = 6 \sqrt{2} \times 10^{- 8} = 8.5 \times 10^{- 8} T$

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