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In an electric field shown in figure, three equipotential surfaces are shown. If function of electric field is $E = 2 x^{2} {Vm}^{- 1}$ , and given that $V_{1} - V_{2} = V_{2} - V_{3},$ then we have

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$x_{2} > x_{1}$

$x_{1} > x_{2}$

data insufficient

$x_{1} = x_{2}$

answer is B.

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Detailed Solution

As E increases along x-axis, same potential drop will occur for lesser values of distance. Hence $x_{2} < x_{1} .$

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