In an electrolysis experiment, a current was passed for hours through cells connected in series. The first cell contains the solution of gold salt and the second cell contains copper sulphate solution. gold was deposited in the first cell. If the oxidation number of golds isThe amount of copper deposited on the cathode in the second cell is ____. Also the magnitude of current in ampere is ____.

Question

In an electrolysis experiment, a current was passed for hours through cells connected in series. The first cell contains the solution of gold salt and the second cell contains copper sulphate solution. gold was deposited in the first cell. If the oxidation number of golds isThe amount of copper deposited on the cathode in the second cell is . Also the magnitude of current in ampere is .

Accepted Answer

Concept- According to Faraday's Second Law of Electrolysis the mass of a substance accumulated or discharged at any electrode on passing a certain amount of charge is directly proportional to its chemical equivalent weight.

Equivalent mass is basically equal to its molar mass divided by valency factor.
For acids, the valency factor is equal to their basicity and for bases, the valency factor is equal to their acidity.
3 is the valency factor for Gold, Au. Therefore,

2 is the valency factor for Copper,

. Therefore,

Therefore, the amount of copper deposited,
Question Image

Let Z be the electrochemical equivalent of Cu

We know that,

As,

seconds
mass of copper deposited

Therefore,
Question Image

Hence, the amount of copper deposited is

and the magnitude of current is

ampere.