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Q.

In an electrolyte 3.2  ×  1018 bivalent positive ions drift to the right per second while 3.6  ×  1018 monovalent negative ions drift to the left per second. Then the current is

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a

1.6 A to the right

b

1.6 A to the left

c

0.45 A to the right

d

0.45 A to the left

answer is B.

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Detailed Solution

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Netcurrent  inet=i++  i

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=n+q+t+nqt=n+t×2e+nt×e=3.2×1018×2×1.6×1019+3.6×1018×1.6×1019

1.6 A (towards right)

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In an electrolyte 3.2  ×  1018 bivalent positive ions drift to the right per second while 3.6  ×  1018 monovalent negative ions drift to the left per second. Then the current is