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In an electromagnetic wave in vacuum. The electrical and magnetic field are $40 π V / m$ and $0.4 \times 10^{- 7} T$ . The pointing vector

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$4.4 W m^{- 1}$

$0.44 W m^{- 1}$

$5.65 W m^{- 1}$

$4.0 W m^{- 1}$

answer is D.

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Detailed Solution

$\vec{S} = \frac{\vec{E} \times \vec{M}}{μ_{0}} = \frac{0.4 \times 10^{- 7} \times 40 π}{4 π \times 10^{- 7}}$

$\Rightarrow 0.4 \times 10 = 4$

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