In an electromagnetic wave, the amplitude of electric field is $1 V m^{- 1}$ . Choose the correct option(s)

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Average energy density of magnetic field is $2.2125 \times 10^{- 12} J m^{- 3}$

Average energy density of electric field is $2.2125 \times 10^{- 12} J m^{- 3}$

Average energy density of wave is $4.425 \times 10^{- 12} J m^{- 3}$

The amplitude of magnetic field is 3.33nT

answer is A, B, C, D.

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Detailed Solution

$\frac{E_{0}}{B_{0}} = C$

$U_{E} = U_{B} = \frac{1}{4} ε_{0} E^{2}$

$U = U_{E} + U_{B}$

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