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Q.

In an electromagnetic wave, the electric field oscillates sinusoidally with amplitude $48 {Vm}^{- 1} .$ The RMS value of oscillating magnetic field will be

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a

$16 \times 10^{- 9} T$

b

$11.3 \times 10^{- 8} T$

c

$1.6 \times 10^{- 8} T$

d

$144 \times 10^{8} T$

answer is D.

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Detailed Solution

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$B_{0} = \frac{E_{0}}{c} = \frac{48}{3 \times 10^{8}} = 16 \times 10^{- 8} T$

$B_{rms} = \frac{B_{0}}{\sqrt{2}} = \frac{16 \times 10^{- 8}}{\sqrt{2}} = 8 \sqrt{2} \times 10^{- 8} T$

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