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In an electroplating experiment m g of silver is deposited, when 4 amperes of current flows for 2 minutes. The amount (in g) of silver deposited by 6 amperes of current flowing for 40 seconds will be

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4 m

m/4

m/2

2 m

answer is C.

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Detailed Solution

$\begin{array}{l} m = Z \times 4 \times 120; M = Z \times 6 \times 40 \\ \frac{M}{m} = \frac{6 \times 40}{4 \times 120} = \frac{1}{2}; M = m / 2 \end{array}$

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