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Q.

In an estimation of bromine by Carius method, 1.6 g of an organic compound gave 1.88 g of AgBr. The mass percentage of bromine in the compound is ……… (Atomic mass, Ag=108 g  mol−1 , Br=80 g  mol−1 )

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answer is 50.

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Detailed Solution

if molar mass of compound is M
1.6/M = 1.88/188 = 0.01
so m = 160 gram / mole
Now % of bromine = 80/160 x 100% 50%
 

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