In an evacuated vessel of capacity 49.2 L, 4 moles of Ar(g) and 5 moles of PCl5(g) were introduced and the temperature is maintained at 240K (assume that at this temperature decomposition of PCl5 takes place). At equilibrium, the total pressure of the mixture was found to be 4.8atm. (Given R=0.082atm L mol−1K−1). Correct statement(s) is/are

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In an evacuated vessel of capacity 49.2 L, 4 moles of Ar(g) and 5 moles of $P C l_{5} (g)$ were introduced and the temperature is maintained at 240K (assume that at this temperature decomposition of $P C l_{5}$ takes place). At equilibrium, the total pressure of the mixture was found to be 4.8atm. (Given $R = 0.082 a t m L m o l^{- 1} K^{- 1}$ ). Correct statement(s) is/are

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The degree of dissociation $P C l_{5} (g) into P C l_{3} (g) & C l_{2} (g)$ is 0.6.

At equilibrium total moles of gases are 12.

$K_{p}$ for the reaction $P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$ is 2.7atm.

On removing Ar(g) from the equilibrium mixture at constant pressure and temperature, the extent of dissociation of $P C l_{5}$ will increase

answer is A, C.

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Detailed Solution

$P \underset{\begin{array}{l} 5 \\ 5 - x \end{array}}{C l_{5}} (g) ⇌ \underset{\begin{array}{l} x \end{array}}{P C l_{3} (g)} + \underset{\begin{array}{l} x \end{array}}{C l_{2} (g)}$

$m_{r} = 4 + 5 - x + x + x$ $= 9 + x$

$K_{p} = \frac{\frac{3}{12} \times 4.8 \times \frac{3}{12} \times 4.8}{\frac{2}{12} \times 4.8} = \frac{3}{12} \times \frac{4.8 \times 3}{2} = 1.8 a t m$