In an evacuated vessel of capacity 49.2 L, 4 moles of Ar(g) and 5 moles of $P C l_{5} (g)$ were introduced and the temperature is maintained at 240K (assume that at this temperature decomposition of $P C l_{5}$ takes place). At equilibrium, the total pressure of the mixture was found to be 4.8atm. (Given $R = 0.082 a t m L m o l^{- 1} K^{- 1}$ ). Correct statement(s) is/are

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The degree of dissociation $P C l_{5} (g) into P C l_{3} (g) & C l_{2} (g)$ is 0.6.

$K_{p}$ for the reaction $P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$ is 2.7atm.

At equilibrium total moles of gases are 12.

On removing Ar(g) from the equilibrium mixture at constant pressure and temperature, the extent of dissociation of $P C l_{5}$ will increase

answer is C, A.

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Detailed Solution

$P \underset{\begin{array}{l} 5 \\ 5 - x \end{array}}{C l_{5}} (g) ⇌ \underset{\begin{array}{l} x \end{array}}{P C l_{3} (g)} + \underset{\begin{array}{l} x \end{array}}{C l_{2} (g)}$

$m_{r} = 4 + 5 - x + x + x$ $= 9 + x$

$K_{p} = \frac{\frac{3}{12} \times 4.8 \times \frac{3}{12} \times 4.8}{\frac{2}{12} \times 4.8} = \frac{3}{12} \times \frac{4.8 \times 3}{2} = 1.8 a t m$