In an experiment 0.22 g of magnesium pyrophosphate was produced from 0.1 g of an organic compound. The percentage of phosphorus in it is:

$\mathrm{P} \% = \frac{62}{222} \times \frac{{\mathrm{w}}_{\mathrm{ppt}}}{\mathrm{w}} \times 100 = \frac{62}{222} \times \frac{0.22}{0.1} \times 100 = 61.44\%$

where,   

 ${\mathrm{W}}_{\mathrm{ppt}.}$ = Weight of Magnesium pyro phosphate.

W = Weight of Organic compound.