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Q.

In an experiment for determining the gravitational acceleration g of a place with the help of a simple pendulum, the measured time period square is plotted against the string length of the pendulum in the figure. What is the value of g at the place?

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a

9.87 m/s2

b

9.91 m/s2

c

10.0 m/s2

d

9.81 m/s2

answer is B.

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Detailed Solution

T2=4π2gl ∴Slope = m=4π2g From graph, slope is m=61.5=4

∴4=4π2g; g=π2=9.87 m/s2

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