In an experiment, hydrochloric acid was reacted with calcium carbonate at room temperature and pressure. If  801 cm³ of gas X was produced then, the number of mole and mass of gas X given off are respectively.

$$\begin{gathered} \begin{array}{l}{\text{CaCO}}_{\text{3}}+2\text{HC}l\to \text{CaC}{l}_2+{\text{CO}}_{\text{2}}+{\text{H}}_{\text{2}}\text{O}\\ \text{ 80\hspace{0.17em}ml}\end{array} \\ \begin{array}{l}?\to 273\mathrm{K}\\ \mathrm{PV}=\mathrm{nRT}\\ \frac{\mathrm{V}}{\mathrm{T}}=\mathrm{K}\\ \frac{80}{298}=\frac{{\mathrm{V}}_2}{273}\\ \frac{273\times 80}{298}\Rightarrow 73.2\mathrm{ml}\\ 22.4\times {10}^3\mathrm{ml}\to 1\mathrm{mole}\text{ of }{\mathrm{CO}}_2\\ 72\mathrm{ml}\to ?\mathrm{m}\text{ ole of }{\mathrm{CO}}_2\\ \frac{72}{22.4\times {10}^3}\Rightarrow 3.27\times {10}^{-3}\mathrm{moles}\\ \text{ mass }\Rightarrow 3.27\times {10}^{-3}\times 44\mathrm{g}\Rightarrow 0.14388\mathrm{g}\end{array} \end{gathered}$$