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Q.

In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is $6600 A^{o}$ , then wavelength of first maximum will be

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a

$3300 A^{o}$

b

$4400 A^{o}$

c

$5500 A^{o}$

d

$6600 A^{o}$

answer is B.

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Detailed Solution

`In a single slip experiment,
For diffraction maximum,
$a \sin θ = (2 n + 1) \frac{λ}{2}$
And for diffraction minima, $(2 \times 1 + 1) \frac{λ}{2} = 1 \times 600 (∵ λ_{R} = 6600 A^{0})$
$\Rightarrow λ = \frac{6600 \times 2}{3} \Rightarrow λ 4400 A^{0}$

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