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Q.

In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line one may conclude that

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a

R(T)=R0T2

b

R(T)=R0eT02/T2

c

R(T)=R0eT2/T02

answer is B.

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Detailed Solution

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Equation of straight line from graph

y=−mx+c

⇒lnR=−m(1T2)+c

Here, m&care constants

R=e[−m(1T2)+c]=e−m(1T2)×ec⇒R(T)=R0e−T02T2

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