In an experiment, the values of refractive indices of glass were found to be 1.54, 1.53, 1.44, 1.54, 1.56 and 1.45 in successive measurements
i) mean value of refractive index of glass
ii) mean absolute error
iii) relative error and
iv) percentage error are respectively,

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1.51, 0.4, 0.03, 3%

15.1, 0.04, 0.3, 3%

1.51, 0.04, 0.03, 3%

15.1, 0.04, 0.03, 3%

answer is A.

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Detailed Solution

$i) Mean = \frac{1.54 + 1.53 + 1.44 + 1.54 + 1.56 + 1.45}{6}$
x=1.51
ii) Mean absolute error $Δx = \frac{0.03 + 0.02 + 0.07 + 0.03 + 0.05 + 0.06}{6} = 0.04$
$iii) relative error = \frac{Δx}{x} = \frac{0.04}{1.51} = 0.03$
$iv) percentage error = \frac{Δx}{x} \times 100$
=0.03 × 100 = 3%