In an experiment to verify Stokes law, a small sphericall ball of radius r and density $ρ$ falls under gravity through a distance h in air before entering a tank of water. If the terminal velocity of the ball inside water is same as its velocity just before entering the water surface, then the value of h is proportional to (ignore viscosity of air)

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$r^{4}$

$r$

$r^{3}$

$r^{2}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$V_{T} = \frac{2}{9} \frac{r^{2} (ρ - σ) g}{n}$

After falling ‘h’ distance is attains terminal velocity

$\sqrt{2 g h} = \frac{2}{9} \frac{r^{2} (ρ - σ) g}{n}$

$∴ n \propto r^{4}$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test