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In an explosion a body at rest breaks up in to 3 parts. Two parts having equal masses move in mutually perpendicular directions each with a velocity of 12 m/s. The magnitude of velocity of the third part which has 3 times mass of each part is given by $\frac{N}{\sqrt{2}} .$ Find the value of $N$

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Detailed Solution

The momentum of third part will be equal and opposite of the resultant of momentum of rest two equal parts

Let u be the velocity of third part. By the conservation of linear momentum, $3 m \times u = m \times 12 \sqrt{2} \Rightarrow u = 4 \sqrt{2} m/s$

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