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Q.

In an F2 population of 96 plants produced from a Mendelian cross of RRYY (round yellow) and rryy (wrinkled – green) how many plants will be homozygous (RRyy)?

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a

8

b

16

c

24

d

6

answer is C.

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Detailed Solution

1/16 of the total F2 population are homozygous round green. So, the proportion of plants with the RRyy genotype would be 1/16 of 96. 1/16 * 96 = 6.

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