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In an ideal transformer, the voltage and the current in the primary coil are 200 V and 2 A, respectively. If the voltage in the secondary coil is 2000 V then the value of current in the secondary coil will be

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10 A

20 A

2 A

0.2 A

answer is A.

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Detailed Solution

Given:
Voltage in primary coil , V_p = 200 V
Current in primary coil , i_p = Z A
Voltage in secondary coil, V_s = 2000 V
The relation for the current in the secondary coil is

$\frac{v_{s}}{v_{p}} = \frac{i_{p}}{i_{s}} = \frac{2000}{200} = \frac{2}{i_{s}} = \frac{2 \times 200}{2000} = 0.2 A$

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