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In an insulated container 1 mole of an ideal gas is reversibly expanded to 600 k to 300 k calculate the work done by the gas if the gas is a diatomic

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-6235.5 J

-3779.1 J

+6235.5J

+3779.1 J

answer is A.

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Detailed Solution

For a diatomic gas $(∵ γ = 1 .40)$
$\begin{array}{l} w = \frac{nR}{γ - 1} (T_{2} - T_{1}) \\ = \frac{1 \times 8 .314}{1 .40 - 1} (300 - 600) = - 6235 .5 J \end{array}$

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