In an interference pattern, at a point there observe 16th order maximum for λ1=6000 A0 .What order will be visible here if the source is replaced by light of wavelength λ2=4800 A0 ?

The distance of nth maxima from central maxima is given by yn=nDλd, for yn to be constant, nλ = constant. Thus n1λ1=n2λ2∴n2=n1λ1λ2=16×60004800=20

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In an interference pattern, at a point there observe 16^th order maximum for $λ_{1} = 6000 \overset{0}{A}$ .What order will be visible here if the source is replaced by light of wavelength $λ_{2} = 4800 \overset{0}{A}$ ?

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answer is 20.

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Detailed Solution

The distance of nth maxima from central maxima is given by $y_{n} = n \frac{Dλ}{d}$ , for y_n to be constant, n $λ$ = constant. Thus $n_{1} λ_{1} = n_{2} λ_{2}$
$∴ n_{2} = \frac{n_{1} λ_{1}}{λ_{2}} = \frac{16 \times 6000}{4800} = 20$

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