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Q.

In an interference, the intensity of two interfering waves are I and 4I respectively. They produce intensity at two points A and B with phase angle of π/2 and π respectively. Then difference in intensity between them is 

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a

I

b

5I

c

4I

d

2I

answer is C.

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Detailed Solution

 

{I_R} = {I_1} + {I_2} + 2\sqrt {{I_1}} \sqrt {{I_2}} \cos \phi \
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\therefore I_A-I_B=4I
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