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In an irreversible process taking place at constant P and T in which only pressure volume work is being done by the system the change in Gibb's energy $(∆ G)$ and change in entropy $(∆ S),$ satisfy the criterion

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${(∆ S)}_{V . U} = 0, {(∆ G)}_{T, P} = 0$

${(∆ S)}_{V . U} = 0, {(∆ G)}_{T, P} = + ve$

${(∆ S)}_{V . U} = - ve, {(∆ G)}_{T, P} = - ve$

${(∆ S)}_{V . U} = + ve, {(∆ G)}_{T, P} = - ve$

answer is D.

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Detailed Solution

For a spontaneous change (work is being done by the system) ${(dG)}_{T, P} = - ve and {(dS)}_{V, U} = + ve$

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