In an isobaric process △Q=Kγγ−1 where γ=Cp/Cv. what is K?

△Q=Kγγ−1=KCP/Cv(CP/Cv)−1=KCPCP−Cv=K(nCP△T)(nCP△T−nCv△T)=K△Q(△Q−△U)=K△Q△W Or 1=K△WK=ΔW

In an isobaric process △Q=Kγγ−1 where γ=Cp/Cv. what is K?

△Q=Kγγ−1=KCP/Cv(CP/Cv)−1=KCPCP−Cv=K(nCP△T)(nCP△T−nCv△T)=K△Q(△Q−△U)=K△Q△W Or 1=K△WK=ΔW

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In an isobaric process $△ Q = \frac{K γ}{γ - 1}$ where $γ = C_{p} / C_{v} .$ what is $K$ ?

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Pressure

$Δ W$

Volume

$Δ U$

answer is D.

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Detailed Solution

$△ Q = \frac{K γ}{γ - 1} = \frac{K C_{P} / C_{v}}{(C_{P} / C_{v}) - 1} = \frac{K C_{P}}{C_{P} - C_{v}}$

$= \frac{K (n C_{P} △ T)}{(n C_{P} △ T - n C_{v} △ T)} = \frac{K △ Q}{(△ Q - △ U)} = \frac{K △ Q}{△ W} O r 1 = \frac{K}{△ W}$

$K = Δ W$

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In an isobaric process △Q=Kγγ−1 where γ=Cp/Cv. what is K?

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In an isobaric process $△ Q = \frac{K γ}{γ - 1}$ where $γ = C_{p} / C_{v} .$ what is $K$ ?