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In an isosceles triangle, the angles opposite to the equal sides are ____.


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Detailed Solution

     Let ABC be an isosceles triangle and AD be the bisector of side BC
In ∆ABD and ∆ACD,
AB = AC   (given)
BD = DC   (AD is a bisector)
AD=AD   (common)
By SSS congruence,
∆ABD ≅ ∆ACD ∠B = ∠D  (by CPCT)
Thus, the angles opposite to equal sides are equal.
 
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