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In an n-p-n transistor circuit, the collector current is 10mA if 90% of the electrons emitted reach the collector

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The base current will be 1mA

The emitter current will be 9mA

The base current will be -1mA

The emitter current will be 11mA

answer is B, C.

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Detailed Solution

If 90% electrons reaches the collector then

$0.9 i_{e} = i_{c}$

$i_{e} = \frac{i_{c}}{0.9}$

$i_{e} = 11 m A$

$i_{e} = i_{c} + i_{b}$

$i_{b} = 11 - 10$

$i_{b} = 1 m A$

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