In an NPN transistor circuit the collector current is 10mA. If 90% of the electrons are able to reach the collector from emitter
a. The emitter current will be 9mA b. The emitter current will be 11mA
c The base current will be 1.1 mA d. The base current will be 0.1 mA

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b and d are correct

a and c are correct

a and d are correct

b and c are correct

answer is D.

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Detailed Solution

90% of emitter current is collector current and 10 % will be base current

90% of $I_{E}$ is 10mA $I_{E} = \frac{10 \times 100}{90} = 11.1 m A$ $I_{B} = 1.1 m A$

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