In an orbit of radius 0.5A an electron revolves with a frequency of 6.25 x 1015 Hz. The magnetic induction field at its centre is

I=efe=1.6 x 10-19 Cf = 6.25 x 1015 HzB=μ0I2r=4×π×10−7×1.6×10−19×6.25×10152×0.5×10−10=4π Tesla

In an orbit of radius 0.5A an electron revolves with a frequency of 6.25 x 1015 Hz. The magnetic induction field at its centre is

I=efe=1.6 x 10-19 Cf = 6.25 x 1015 HzB=μ0I2r=4×π×10−7×1.6×10−19×6.25×10152×0.5×10−10=4π Tesla

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In an orbit of radius 0.5A an electron revolves with a frequency of 6.25 x 10¹⁵ Hz. The magnetic induction field at its centre is

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4 $π$ tesla

2 $π$ tesla

4 tesla

2 tesla

answer is A.

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Detailed Solution

I=ef
e=1.6 x 10^-19 C
f = 6.25 x 10¹⁵ Hz
$\begin{array}{l} B = \frac{μ_{0} I}{2 r} \\ = \frac{4 \times π \times 10^{- 7} \times 1.6 \times 10^{- 19} \times 6.25 \times 10^{15}}{2 \times 0.5 \times 10^{- 10}} \\ = 4 π Tesla \end{array}$

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In an orbit of radius 0.5A an electron revolves with a frequency of 6.25 x 1015 Hz. The magnetic induction field at its centre is

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In an orbit of radius 0.5A an electron revolves with a frequency of 6.25 x 10¹⁵ Hz. The magnetic induction field at its centre is