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In an organic compound, phosphorous is estimated as

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${Mg}_{2} P_{2} O_{7}$

$H_{3} {PO}_{4}$

$P_{2} O_{5}$

${Mg}_{3} {({PO}_{4})}_{2}$

answer is C.

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Detailed Solution

${Mg}_{2} P_{2} O_{7}$ used to estimate phosphorous in organic compound $% P = \frac{62}{222} \times \frac{Mass of {Mg}_{2} P_{2} O_{7}}{Mass of O.C.} \times 100$

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