In an Ostwald process,

The reaction includes in the first step is ${\mathrm{NH}}_3+{\mathrm{O}}_2 \stackrel{\mathrm{Pt}}{\to } \mathrm{X} + {\mathrm{H}}_2\mathrm{O}$.

The reaction includes in the second step is $\mathrm{X}+ {\mathrm{O}}_2 \to \mathrm{Y}$.

The reaction includes in the third step is $\mathrm{Y} +{\mathrm{O}}_2+ {\mathrm{H}}_2\mathrm{O}\to \mathrm{Z}$

Choose the incorrect option is :

$4{\mathrm{NH}}_3+5{\mathrm{O}}_2\stackrel{\mathrm{platinium}}{\to }\underset{\mathrm{X}}{4\mathrm{NO}}+6{\mathrm{H}}_2\mathrm{O}+\mathrm{heat}$

$\underset{\mathrm{X}}{2\mathrm{NO}}+{\mathrm{O}}_2\to \underset{\mathrm{Y}}{2{\mathrm{NO}}_2}+\mathrm{heat}$

$\underset{\mathrm{Y}}{4{\mathrm{NO}}_2}+{\mathrm{O}}_2+2{\mathrm{H}}_2\mathrm{O}\to \underset{\mathrm{Z}}{4{\mathrm{HNO}}_3}+\mathrm{heat}$

• NO is paramagnetic because it has one unpaired electron present in its $\mathrm{\pi }$ anti-bonding orbital $(\mathrm{\pi }*).$
• NO is a neutral oxide because it neither shows acidic property nor basic property. NO₂ is an acidic oxide because it forms acid on reaction with water.
• The oxidation state of N in HNO₃ is +5. N already present in its highest oxidation state, thereby it can readily reduced and acts as a strong oxidizing agent.
• Both NO₂ and HNO₃ are acidic in nature, as NO₂ is an acidic oxide and HNO₃ is nitric acid.